Election in Arkansas
1852 United States presidential election in Arkansas
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| |  |  | | Nominee | Franklin Pierce | Winfield Scott | | | Party | Democratic | Whig | | Home state | New Hampshire | New Jersey | | Running mate | William R. King | William A. Graham | | Electoral vote | 4 | 0 | | Popular vote | 12,173 | 7,404 | | Percentage | 62.18% | 37.82% | |
 County Results | Pierce 50-60% 60-70% 70-80% 80-90% 90-100% | Scott 50-60% | No Vote: | |
President before election
Millard Fillmore
Whig | Elected President
Franklin Pierce
Democratic | |
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| Mayoral elections |
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- 1996
- 2000
- 2004
- 2008
- 2012
- 2016
- 2020
- 2024
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| Mayoral elections |
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- 1996
- 2000
- 2004
- 2008
- 2012
- 2016
- 2020
- 2024
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| Mayoral elections |
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- 1996
- 2000
- 2004
- 2008
- 2012
- 2016
- 2020
- 2024
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The 1852 United States presidential election in Arkansas took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Arkansas voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Arkansas by a margin of 24.36%.
Results
See also
References
- ^ "1852 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved December 1, 2017.
- ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 1, 2017.
