Sutatausa

Municipality and town in Cundinamarca, Colombia

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Location of the municipality and town inside Cundinamarca Department of Colombia

5°14′50″N 73°51′9″W / 5.24722°N 73.85250°W / 5.24722; -73.85250Country

ColombiaDepartment

CundinamarcaProvinceUbaté ProvinceFounded24 June 1537Founded byHernán Pérez de QuesadaGovernment

• MayorHugo Orlando Santa Rodríguez
(2016-2019)Area

• Municipality and town67 km² (26 sq mi)Elevation

2,550 m (8,370 ft)Population

(2015)

• Municipality and town5,564 • Density83/km² (220/sq mi) • Urban

1,743Time zoneUTC-5 (Colombia Standard Time)WebsiteOfficial website

Sutatausa (Spanish pronunciation: [sutaˈtawsa]) is a municipality and town of Colombia in the Ubaté Province, part of the department of Cundinamarca. The municipality is located on the Altiplano Cundiboyacense at a distance of 88 kilometres (55 mi) from the capital Bogotá and borders Ubaté in the north, Tausa in the south, Cucunubá in the east and Carmen de Carupa and Tausa in the west.^[1]

Etymology

The name Sutatausa comes from Chibcha and means "small tribute".^[1]

History

The area of Sutatause before the Spanish conquest was inhabited by the Muisca, organised in their loose Muisca Confederation. Sutatausa was ruled by the zipa based in Muyquytá.

Modern Sutatausa was founded on June 24 (Saint John's day), 1537 by Hernán Pérez de Quesada, brother of conquistador Gonzalo Jiménez de Quesada, who on the same day founded Tenza.^[1]